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js jsonArrAy 遍历

var typeArr = new Array();for(var i = 0;i

json 数组也是数组 //1、var jsonstr="[{'name':'a','value':1},{'name':'b','value':2}]";var jsonarray = eval('('+jsonstr+')'); var arr = { "name" : $('#names').val(), "value" : $('#values').val() }jsonarray.push(arr);//2、var json...

jq框架下,给个示例,仅供参考: var objs = $.parseJSON('[{"name":"aaa","age":"22"},{"name":"bbb","age":"33"}]');var str = '';$.each(objs, function(k, obj){ str += obj.name + ' is ' + obj.age + "\n";});alert(str);

//传入要查找的数据集,目标id,返回目标ID对应的数据集合 //jsonData:数据集 //destID:目标ID //json:目标ID结果集 function GetSubJson(jsonData, destID, json) { for (var i = 0; i < jsonData.length; i++) { if (jsonData[i].id == destID...

json.a[1],还有你的这个json是有问题的,数组不要用‘’号引起来! var json={ a:["aaaaa","bbbbb","ccccc"], b:["11111","22222","33333"] };

如果这个数组不是json的话,就可以for(var i=0;i

例如数据库里面的json字符串是这样的 ? 1 2 3 4 5 var str = '[{"name":"宗2瓜","num":"1","price":"122"},{"name":"宗呱呱","num":"1","price":"100"}]'; var xqo = eval('(' + str + ')'); for(var i in xqo){ alert(xqo[i].name); } 上面的是...

var jsondata = yourdata; for(var x in jsondata){ document.write(x+"="+jsondata[x]); } 如果是jsonarray就外面套一层for即可 var jsonarray =yourarray; for(var i =0;i

var jsondata = yourdata; for(var x in jsondata){ document.write(x+"="+jsondata[x]); } 如果是jsonarray就外面套一层for即可 var jsonarray =yourarray; for(var i =0;i

var origin = [{"first_id":1,"first_name":"中学","second_id":"1-1","second_name":"一年级","third_id":"1-1-1","third_name":"一年级一班","people":10,"age":10,"parent":5},{"first_id":1,"first_name":"中学","second_id":"1-1","second_...

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